overtaking sight distance based Numericals

overtaking sight distance based Numericals

SSC JE MAINS 2018 QUESTIONS WITH SOLUTIONS 






The Speed of overtaking and overtaken vehicle are 70 and 40 KMPH respectively on a two way traffic Road.The average acceleration during overtaking maybe Assumed as 0.99m/s2. 

i) calculate safe Overtaking Sight distance taking? 

ii) what is the minimum length of overtaking zone and draw a neat sketch of the overtaking zone and show the positions of sign post

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SSC JE MAINS PAPER SOLUTIONS

SSC JE MAINS PAPER SOLUTIONS 

CIVIL ENGINEERING CONVENTIONAL PAPER SOLUTIONS 2018


QUESTION NO--01

(a) For A Town with population of of 200000 a water supply scheme is to be designed.The maximum daily demand may be assumed as 200 litre per capita per daY. The storage Reservoir is situated 5 kilometre away from the town. Assuming loss of head from source to town as 10m and coefficient of friction for the pipe material as 0.012, recommend the size of supply main. 50% of the daily demand has to be pumped in 8 hours for the purposed scheme.


Solutions-
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Solution:-
 Maximum Daily Water Demand = 200 LPCD 
Maximum Water Demand = 200000 x 200 = 40 MLD 
Maximum Water Demand for which supply main is to be designed = 50% of daily demand 

Q = (50 / 100) x 40 x 106
 Liters per 8 hours 

Q = (50 / 100) x (40 x 106) / (8 x 60 x 60) 
Q = 0.694 m3/s
 L = 5000 m HL
 = 10 m f = 0.048 
HL
 = (f * L*v2) / (2gd) 
10 = (0.048 x 5000 x v2) / (2 x 9.81 x d) 
v = ( Q / (∏ /4)) x d2 v = ( 0.694 / (3.14/4)) x d2
 v = 0.884 d2 
10 = (0.048 x 5000 x (0.884 d2)2) / (2 x 9.81 x d) 


d = 0.955 m




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